y^2/3=2-y^4

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Solution for y^2/3=2-y^4 equation: 


y in (-oo:+oo)

(y^2)/3 = 2-y^4 // - 2-y^4

y^4+(y^2)/3-2 = 0

y^4+1/3*y^2-2 = 0

t_1 = y^2

1*t_1^2+1/3*t_1^1-2 = 0

t_1^2+1/3*t_1-2 = 0

DELTA = (1/3)^2-(-2*1*4)

DELTA = 73/9

DELTA > 0

t_1 = ((73/9)^(1/2)-1/3)/(1*2) or t_1 = (-(73/9)^(1/2)-1/3)/(1*2)

t_1 = ((73/9)^(1/2)-1/3)/2 or t_1 = (-((73/9)^(1/2)+1/3))/2

t_1 = (-((73/9)^(1/2)+1/3))/2

y^2-((-((73/9)^(1/2)+1/3))/2) = 0

y^2+(1/2)*((73/9)^(1/2)+1/3) = 0

1*y^2 = -(1/2*((73/9)^(1/2)+1/3)) // : 1

y^2 = -1/2*((73/9)^(1/2)+1/3)

t_1 = ((73/9)^(1/2)-1/3)/2

y^2-(((73/9)^(1/2)-1/3)/2) = 0

1*y^2 = ((73/9)^(1/2)-1/3)/2 // : 1

y^2 = ((73/9)^(1/2)-1/3)/2

y^2 = ((73/9)^(1/2)-1/3)/2 // ^ 1/2

abs(y) = (((73/9)^(1/2)-1/3)^(1/2))/(2^(1/2))

y = (((73/9)^(1/2)-1/3)^(1/2))/(2^(1/2)) or y = -((((73/9)^(1/2)-1/3)^(1/2))/(2^(1/2)))

y in { (((73/9)^(1/2)-1/3)^(1/2))/(2^(1/2)), -((((73/9)^(1/2)-1/3)^(1/2))/(2^(1/2))) }

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